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Home > Archive > Alternative Power sources > November 2005 > Adding Up Battery Amp-Hours?
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Adding Up Battery Amp-Hours?
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| Antipodean Bucket Farmer 2005-10-02, 6:21 am |
| Hi, Everybody,
Let's say that I want to make a small 12-volt battery
supply. So I use a pair of cheap 6-volt sealed gel
cells, in series.
Each of the two batteries is rated at, say,
5 Amp-Hours.
Will they add together, for a total of 10 Amp-Hours?
Or will the pair just provide 5 AH at the higher
voltage (I.e. 12-volts)?
Thanks...
--
Get Credit Where Credit Is Due
http://www.cardreport.com/
Credit Tools, Reference, and Forum
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"Antipodean Bucket Farmer" <usenet2005@THE-DOMAIN-IN.SIG> wrote in message
news:MPG.1da93345ccb09a61989968@news.xtra.co.nz...
> Hi, Everybody,
>
> Let's say that I want to make a small 12-volt battery
> supply. So I use a pair of cheap 6-volt sealed gel
> cells, in series.
>
> Each of the two batteries is rated at, say,
> 5 Amp-Hours.
>
> Will they add together, for a total of 10 Amp-Hours?
> Or will the pair just provide 5 AH at the higher
> voltage (I.e. 12-volts)?
>
> Thanks...
>
> Series will be 5Ah at 12 volts. Parrallel will be 10Ah at 6 volts.
>
> --
> Get Credit Where Credit Is Due
> http://www.cardreport.com/
> Credit Tools, Reference, and Forum
| |
| Ron Rosenfeld 2005-10-02, 8:21 am |
| On Sun, 2 Oct 2005 00:59:54 -0700, Antipodean Bucket Farmer
<usenet2005@THE-DOMAIN-IN.SIG> wrote:
>Hi, Everybody,
>
>Let's say that I want to make a small 12-volt battery
>supply. So I use a pair of cheap 6-volt sealed gel
>cells, in series.
>
>Each of the two batteries is rated at, say,
>5 Amp-Hours.
>
>Will they add together, for a total of 10 Amp-Hours?
>Or will the pair just provide 5 AH at the higher
>voltage (I.e. 12-volts)?
>
>Thanks...
5AH @ 12V
-- ron (off the grid in Downeast Maine)
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| GeekBoy 2005-10-02, 1:21 pm |
|
"Tim" <beachcooler@earthlink.net> wrote in message
news:FbN%e.6934$vw6.6700@newsread1.news.atl.earthlink.net...
>
> "Antipodean Bucket Farmer" <usenet2005@THE-DOMAIN-IN.SIG> wrote in message
> news:MPG.1da93345ccb09a61989968@news.xtra.co.nz...
yes that is correct as voltage and amp are inverse of each other. As the
voltage increases the amperage decreases.
Try 4 batteries in series-parallel.
,>>[color=darkred]
>
>
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| Vaughn 2005-10-02, 1:21 pm |
|
"GeekBoy" <GeeksRUs@geek.com> wrote in message
news:433ff4b0$0$27609$8f2e0ebb@news.shared-secrets.com...
>
> yes that is correct as voltage and amp are inverse of each other. As the
> voltage increases the amperage decreases.
HUH? Actually, current (amperage) is directly proportional to voltage and
inversly proportional to resistance.
I (current) = E (voltage) / R (resistance)
Vaughn
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| GeekBoy 2005-10-02, 3:21 pm |
|
"Vaughn" <vaughnsimonHATESSPAM@att.fake.net> wrote in message
news:TFT%e.356826$5N3.145192@bgtnsc05-news.ops.worldnet.att.net...
>
> "GeekBoy" <GeeksRUs@geek.com> wrote in message
> news:433ff4b0$0$27609$8f2e0ebb@news.shared-secrets.com...
>
>
> HUH? Actually, current (amperage) is directly proportional to voltage
> and inversly proportional to resistance.
> I (current) = E (voltage) / R (resistance)
>
Check your forumula
I(current) = Watts / Volts
?(I) = 1000 / 120
?(I) = 1000 / 220
Using ohms law, if you have a 1000 watt hair dryer using 120 volts of
electricity that would result in 8.3 amps of current.
Increasing the voltage to 220 would result in 4.5 amps of current, making
voltage inversive to current. and vis-versa
GB
>
> Vaughn
>
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| Ralph Cameron 2005-10-02, 3:21 pm |
| Each cell is rated at 5 AH so in series they will provide double the voltage
but the same 5 AH.
If you parallel them you'll get 6V at 10AH
"Antipodean Bucket Farmer" <usenet2005@THE-DOMAIN-IN.SIG> wrote in message
news:MPG.1da93345ccb09a61989968@news.xtra.co.nz...
> Hi, Everybody,
>
> Let's say that I want to make a small 12-volt battery
> supply. So I use a pair of cheap 6-volt sealed gel
> cells, in series.
>
> Each of the two batteries is rated at, say,
> 5 Amp-Hours.
>
> Will they add together, for a total of 10 Amp-Hours?
> Or will the pair just provide 5 AH at the higher
> voltage (I.e. 12-volts)?
>
> Thanks...
>
>
>
> --
> Get Credit Where Credit Is Due
> http://www.cardreport.com/
> Credit Tools, Reference, and Forum
| |
| Vaughn 2005-10-02, 4:21 pm |
|
"GeekBoy" <GeekBoy@Geeks.com> wrote in message
news:1128275161.8c5f9c78b8d4b2e74f669706392ce1ae@teranews...
Just noticed that someone x-posted this thread. You can read any further
responses from me at alt.energy.homepower
Vaughn
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| Vaughn 2005-10-02, 4:21 pm |
|
"GeekBoy" <GeekBoy@Geeks.com> wrote in message
news:1128275161.8c5f9c78b8d4b2e74f669706392ce1ae@teranews...
>
> "Vaughn" <vaughnsimonHATESSPAM@att.fake.net> wrote in message
> news:TFT%e.356826$5N3.145192@bgtnsc05-news.ops.worldnet.att.net...
> Check your forumula
>
> I(current) = Watts / Volts
>
> ?(I) = 1000 / 120
> ?(I) = 1000 / 220
>
> Using ohms law, if you have a 1000 watt hair dryer using 120 volts of
> electricity that would result in 8.3 amps of current.
> Increasing the voltage to 220 would result in 4.5 amps of current, making
> voltage inversive to current. and vis-versa
Wrong. You are thinking about the power formula P = I X E
If you were to apply 220 volts to your 110 volt hairdryer, you would (for a
brief amount of time) have 16.66 amps and be producing 4000 watts of heat.
Shortly thereafter, the "magic smoke" would come out, and your hair dryer would
be toast. Current is proportional to voltage and always has been. Read up on
George Ohm's theory.
What you are trying to say is that a 220 volt 1000 watt heater will have half
the current (and twice the resistance) of a 110 volt 1000 watt heater. (P = I X
E) but I is still proportional to E.
Vaughn
>
>
>
> GB
>
>
>
>
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| GeekBoy 2005-10-02, 7:21 pm |
|
"Vaughn" <vaughnsimonHATESSPAM@att.fake.net> wrote in message
news:CLV%e.101869$qY1.56680@bgtnsc04-news.ops.worldnet.att.net...
>
> "GeekBoy" <GeekBoy@Geeks.com> wrote in message
> news:1128275161.8c5f9c78b8d4b2e74f669706392ce1ae@teranews...
>
> Wrong. You are thinking about the power formula P = I X E
>
> If you were to apply 220 volts to your 110 volt hairdryer, you would (for
> a brief amount of time) have 16.66 amps and be producing 4000 watts of
> heat. Shortly thereafter, the "magic smoke" would come out, and your hair
> dryer would be toast. Current is proportional to voltage and always has
> been. Read up on George Ohm's theory.
>
> What you are trying to say is that a 220 volt 1000 watt heater will have
> half the current (and twice the resistance) of a 110 volt 1000 watt
> heater. (P = I X E) but I is still proportional to E.
>
> Vaughn
>
>
I think you better use this calculators
http://www.csgnetwork.com/ohmslaw2.html
>
>
>
>
>
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| Steve Spence 2005-10-02, 9:21 pm |
| Antipodean Bucket Farmer wrote:
> Hi, Everybody,
>
> Let's say that I want to make a small 12-volt battery
> supply. So I use a pair of cheap 6-volt sealed gel
> cells, in series.
>
> Each of the two batteries is rated at, say,
> 5 Amp-Hours.
>
> Will they add together, for a total of 10 Amp-Hours?
> Or will the pair just provide 5 AH at the higher
> voltage (I.e. 12-volts)?
>
> Thanks...
>
>
>
Two 6v 5ah in series is 12v 5ah.
Two 6v 5ah in parallel is 6v 10ah.
--
Steve Spence
Dir., Green Trust, http://www.green-trust.org
Contributing Editor, http://www.off-grid.net
http://www.rebelwolf.com/essn.html
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| Vaughn 2005-10-02, 9:21 pm |
|
"GeekBoy" <GeekBoy@Geeks.com> wrote in message
news:1128290387.338e8f5669072cf90fa7f38d039fa9e0@teranews...
> I think you better use this calculators
I think we are done.
Vaughn
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| GeekBoy 2005-10-02, 10:21 pm |
|
"Vaughn" <vaughnsimonHATESSPAM@att.fake.net> wrote in message
news:mK_%e.358958$5N3.291567@bgtnsc05-news.ops.worldnet.att.net...
>
> "GeekBoy" <GeekBoy@Geeks.com> wrote in message
> news:1128290387.338e8f5669072cf90fa7f38d039fa9e0@teranews...
>
> I think we are done.
Yep since those calculators only show what I was saying
>
> Vaughn
>
>
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| GeekBoy 2005-10-02, 10:21 pm |
|
"Steve Spence" <sspence@green-trust.org> wrote in message
news:is_%e.39098$TA2.17360@fe09.lga...
> Antipodean Bucket Farmer wrote:
>
> Two 6v 5ah in series is 12v 5ah.
> Two 6v 5ah in parallel is 6v 10ah.
And 4 batteries in series-parallel is 12v 10ah
:-D
>
>
> --
> Steve Spence
> Dir., Green Trust, http://www.green-trust.org
> Contributing Editor, http://www.off-grid.net
> http://www.rebelwolf.com/essn.html
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| Steve Spence 2005-10-02, 10:21 pm |
| In-Reply-To: <1128299107.a2f63c169b04e6285acfdca940f12a8b@teranews>
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GeekBoy wrote:
> "Vaughn" <vaughnsimonHATESSPAM@att.fake.net> wrote in message
> news:mK_%e.358958$5N3.291567@bgtnsc05-news.ops.worldnet.att.net...
>
>
>
> Yep since those calculators only show what I was saying
No, you missed it completely.
--
Steve Spence
Dir., Green Trust, http://www.green-trust.org
Contributing Editor, http://www.off-grid.net
http://www.rebelwolf.com/essn.html
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| Steve Spence 2005-10-02, 10:21 pm |
| GeekBoy wrote:
> "Steve Spence" <sspence@green-trust.org> wrote in message
> news:xu_%e.39100$TA2.15032@fe09.lga...
>
>
>
> Yes That is true.
>
Well, that has nothing to do with batteries in series or parallel. You
applied one concept to an unrelated problem.
--
Steve Spence
Dir., Green Trust, http://www.green-trust.org
Contributing Editor, http://www.off-grid.net
http://www.rebelwolf.com/essn.html
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