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| Author |
Ampacity question/problem
|
|
| edannemiller2002@yahoo.com 2007-03-07, 1:25 pm |
| I am trying to calculate the ampacity through a piece of .01"(.
254e-003m) metal. The metal is stainless steel 304, it has a
resistivity of 7.2e-007 ohm-m, a length of .012m, and an area of .
836e-006m^2. There are tons of references to ampacity ratings of
copper and aluminum wires, but no resources I could find that tells
you how they calculate the current carrying capacity of a particular
wire. I just want to know the amount of current this piece of metal
can carry without melting. The melting point of this particular type
of metal is 1400-1455 degrees celcius. Any help or references would
be helpful.
Thanks in advance,
-Erik
| |
| cr500r 2007-03-07, 5:25 pm |
| From ohms law we know that I=SQR(P/R)
meaning the Current = the square root of ( Power / Resistance )
if you calculate how much power that length of wire can radiate in its
environment (based on its surface area, surrounding air etc.) without going
above 1400 C,
(BTW the resistance will change with temperature making this a bit harder)
Take that power (in watts)
divide it by the resistance (in ohms)
and take the square root...
and you have the current in amps!
<edannemiller2002@yahoo.com> wrote in message
news:1173292520.420426.325940@h3g2000cwc.googlegroups.com...
>I am trying to calculate the ampacity through a piece of .01"(.
> 254e-003m) metal. The metal is stainless steel 304, it has a
> resistivity of 7.2e-007 ohm-m, a length of .012m, and an area of .
> 836e-006m^2. There are tons of references to ampacity ratings of
> copper and aluminum wires, but no resources I could find that tells
> you how they calculate the current carrying capacity of a particular
> wire. I just want to know the amount of current this piece of metal
> can carry without melting. The melting point of this particular type
> of metal is 1400-1455 degrees celcius. Any help or references would
> be helpful.
>
> Thanks in advance,
>
> -Erik
>
| |
| MassiveProng 2007-03-07, 8:25 pm |
| On Wed, 07 Mar 2007 21:28:09 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
>From ohms law we know that I=SQR(P/R)
>meaning the Current = the square root of ( Power / Resistance )
>if you calculate how much power that length of wire can radiate in its
>environment (based on its surface area, surrounding air etc.) without going
>above 1400 C,
Ampacity ratings are not about melting points of materials. They
are about preventing temperatures which can cause flashpoint values
for surrounding media.
So the MAX temp you want to reach is well below 450F.
Gaineth thyself a clue.
His solution is to epoxy a temp probe end to the center of a test
section of his medias and feed more and more amperage to it until a
SAFE desired maximum settled in temperature is reached.
THEN, one only REALLY wants to feed such a conductor a huge
percentage LESS than that value in a good, proper design.
IF he wishes to use it as some fusing element, the rep[eatabiltiy
from one to another will likely be pretty bad, and it will pose
hazards if not contained in a glass of flame resistant fiber tube.
| |
| cr500r 2007-03-07, 8:25 pm |
| Your right,
but I was just answering the question he asked, assuming nothing about it.
My guess is it's from a textbook problem in some class, and has about as
much to do with the real world as does your attitude :-)
"MassiveProng" <MassiveProng@thebarattheendoftheuniverse.org> wrote in
message news:spmuu258cna2573ivgpi047qntbigisip1@4ax.com...
> On Wed, 07 Mar 2007 21:28:09 GMT, "cr500r"
> <jeffnope_nospam@hotmail.com> Gave us:
>
>
>
> Ampacity ratings are not about melting points of materials. They
> are about preventing temperatures which can cause flashpoint values
> for surrounding media.
>
> So the MAX temp you want to reach is well below 450F.
>
> Gaineth thyself a clue.
>
> His solution is to epoxy a temp probe end to the center of a test
> section of his medias and feed more and more amperage to it until a
> SAFE desired maximum settled in temperature is reached.
>
> THEN, one only REALLY wants to feed such a conductor a huge
> percentage LESS than that value in a good, proper design.
>
> IF he wishes to use it as some fusing element, the rep[eatabiltiy
> from one to another will likely be pretty bad, and it will pose
> hazards if not contained in a glass of flame resistant fiber tube.
| |
| MassiveProng 2007-03-08, 3:25 am |
| On Thu, 08 Mar 2007 01:29:29 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
>Your right,
You're nothing but a top posting Usenet retard.
It is "You're", dipshit.
You should have paid attention is school, and you should bone up on
the conventions of a forum BEFORE you invade it, interloper.
| |
| edannemiller2002@yahoo.com 2007-03-08, 9:25 am |
| On Mar 8, 3:04 am, MassiveProng
<MassivePr...@thebarattheendoftheuniverse.org> wrote:
> On Thu, 08 Mar 2007 01:29:29 GMT, "cr500r"
> <jeffnope_nos...@hotmail.com> Gave us:
>
>
> You're nothing but a top posting Usenet retard.
>
> It is "You're", dipshit.
>
> You should have paid attention is school, and you should bone up on
> the conventions of a forum BEFORE you invade it, interloper.
I did pay attention is school...most of the time. The piece of metal
will be welded to the base of a lamp (1500W lamp). I just want to be
able to calculate the amount of current that can pass through the
material before the temperature rise becomes too great. Sorry for
asking a question
-Erik
| |
| cr500r 2007-03-08, 1:25 pm |
| It never ceases to amaze me how these self appointed moderators get off on
correcting grammar and spelling.
I'm surprised he didn't use the word "thus" in his stereotypical flame of a
post.
I wonder, does he walk around correcting grammar in real life? A great way
to win friends and influence people!
"MassiveProng" <MassiveProng@thebarattheendoftheuniverse.org> wrote in
message news:9ngvu29ophrd2biilq5t4g4tvm69kc00i3@4ax.com...
> On Thu, 08 Mar 2007 01:29:29 GMT, "cr500r"
> <jeffnope_nospam@hotmail.com> Gave us:
>
>
> You're nothing but a top posting Usenet retard.
>
> It is "You're", dipshit.
>
> You should have paid attention is school, and you should bone up on
> the conventions of a forum BEFORE you invade it, interloper.
| |
| cr500r 2007-03-08, 1:25 pm |
| Erik,
He was just faming me, don't worry about him.
So what voltage lamp?
Is it running off a ballast like a HID lamp?
I really am trying to help here.
<edannemiller2002@yahoo.com> wrote in message
news:1173360163.209555.162000@p10g2000cwp.googlegroups.com...
> On Mar 8, 3:04 am, MassiveProng
> <MassivePr...@thebarattheendoftheuniverse.org> wrote:
>
> I did pay attention is school...most of the time. The piece of metal
> will be welded to the base of a lamp (1500W lamp). I just want to be
> able to calculate the amount of current that can pass through the
> material before the temperature rise becomes too great. Sorry for
> asking a question
>
> -Erik
>
| |
|
| edannemiller2002@yahoo.com wrote:
> On Mar 8, 3:04 am, MassiveProng
> <MassivePr...@thebarattheendoftheuniverse.org> wrote:
>
>
>
> I did pay attention is school...most of the time. The piece of metal
> will be welded to the base of a lamp (1500W lamp). I just want to be
> able to calculate the amount of current that can pass through the
> material before the temperature rise becomes too great. Sorry for
> asking a question
>
> -Erik
>
If you are welding this to the base of a lamp,
then ampacity is a mute point. You cannot use
exposed metal as a conductor and be safe.
You cannot allow the design to cause inductive
heating in that plate and be safe. You need
to use mechanical and electrical construction
that will keep any electrical current away
from exposed metal on that lamp.
MP gave a great description of ampacity. Many
could learn from it.
Ed
| |
| contrex 2007-03-08, 1:25 pm |
| On 8 Mar, 15:46, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
> It never ceases to amaze me how these self appointed moderators get off on
> correcting grammar and spelling.
Well, here's another surprise for you. People outside the USA (They do
exist) are going to wonder what on earth "ampacity" means, until they
realise it's SixPack-talk for "current carrying capacity"
| |
| cr500r 2007-03-08, 1:25 pm |
| http://en.wikipedia.org/wiki/Ampacity
"contrex" <mike.j.harvey@gmail.com> wrote in message
news:1173376966.308990.201860@t69g2000cwt.googlegroups.com...
> On 8 Mar, 15:46, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
>
>
>
> Well, here's another surprise for you. People outside the USA (They do
> exist) are going to wonder what on earth "ampacity" means, until they
> realise it's SixPack-talk for "current carrying capacity"
>
>
| |
| contrex 2007-03-08, 1:25 pm |
| On 8 Mar, 18:07, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
[Top-posted Wikipedia link]
http://en.wikipedia.org/wiki/Ampacity
Yup, as the Wikipedia page says:
(I quote)
"The examples and perspective in this article or section may not
represent a worldwide view of the subject.
Please improve this article or discuss the issue on the talk page."
"Categories: Limited geographic scope | Electricity"
On the talk page:
"If the word "ampacity" is only used in the US, the article should
state this. Otherwise, the article should be edited to be less US-
centric (is there an international standard about ampacity?) Jushi
11:27, 30 November 2006 (UTC)"
Like I said. SixPack-talk.
| |
| cr500r 2007-03-08, 1:25 pm |
| Just another made up word, not really that surprising...
kind of like "SixPack-talk"
BTW I didn't use the word, the original poster did.
"contrex" <mike.j.harvey@gmail.com> wrote in message
news:1173378501.772299.283510@n33g2000cwc.googlegroups.com...
> On 8 Mar, 18:07, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
>
> [Top-posted Wikipedia link]
>
> http://en.wikipedia.org/wiki/Ampacity
>
> Yup, as the Wikipedia page says:
>
> (I quote)
>
> "The examples and perspective in this article or section may not
> represent a worldwide view of the subject.
> Please improve this article or discuss the issue on the talk page."
>
> "Categories: Limited geographic scope | Electricity"
>
> On the talk page:
>
> "If the word "ampacity" is only used in the US, the article should
> state this. Otherwise, the article should be edited to be less US-
> centric (is there an international standard about ampacity?) Jushi
> 11:27, 30 November 2006 (UTC)"
>
> Like I said. SixPack-talk.
>
>
>
| |
| edannemiller2002@yahoo.com 2007-03-08, 5:25 pm |
| On Mar 8, 10:50 am, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
> Erik,
> He was just faming me, don't worry about him.
> So what voltage lamp?
> Is it running off a ballast like a HID lamp?
>
> I really am trying to help here.
>
> <edannemiller2...@yahoo.com> wrote in message
>
> news:1173360163.209555.162000@p10g2000cwp.googlegroups.com...
>
>
>
>
The highest wattage lamp is 1500W, and yes they are HID lamps that run
off a ballast. The piece of metal is welded to the lamp lead wire on
the arc tube. It sits in a detent that is molded into the glass,
where the threads are for screwing on the base. Once the base is
screwed on there is a portion of the metal that folds over the outside
of the base and is secured with a high frequency resistance spot
welder, to prevent the base from coming loose when the lamp is taken
out of a socket. I was using the equation you had stated before to
find the actual resistance of the piece of metal, but i'm still having
trouble relating that to the current carrying capacity(steady state
and transient) that it can handle. I know that the current capacity
needs to be 7A steady state and 15A max(transient), so maybe i'm going
about this wrong and just need to figure out the amount of heat that
is transfered at those current ratings. Any help is greatly
appreciated. I am a programmer and physics is not my strongest point.
Thanks,
-Erik
| |
| edannemiller2002@yahoo.com 2007-03-08, 5:25 pm |
| On Mar 8, 1:58 pm, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
> Just another made up word, not really that surprising...
> kind of like "SixPack-talk"
>
> BTW I didn't use the word, the original poster did.
>
> "contrex" <mike.j.har...@gmail.com> wrote in message
>
> news:1173378501.772299.283510@n33g2000cwc.googlegroups.com...
>
>
>
>
>
>
>
>
>
>
>
>
>
> - Show quoted text -
And the lamp operates at around 260V, with the current around 4.2A. I
don't know if i mentioned that before.
| |
| Gerald C Newton 2007-03-08, 5:25 pm |
|
<edannemiller2002@yahoo.com> wrote in message
news:1173292520.420426.325940@h3g2000cwc.googlegroups.com...
>I am trying to calculate the ampacity through a piece of .01"(.
> 254e-003m) metal. The metal is stainless steel 304, it has a
> resistivity of 7.2e-007 ohm-m, a length of .012m, and an area of .
> 836e-006m^2. There are tons of references to ampacity ratings of
> copper and aluminum wires, but no resources I could find that tells
> you how they calculate the current carrying capacity of a particular
> wire. I just want to know the amount of current this piece of metal
> can carry without melting. The melting point of this particular type
> of metal is 1400-1455 degrees celcius. Any help or references would
> be helpful.
>
> Thanks in advance,
>
> -Erik
>
The Neher McGrath Paper published by IEEE in 1957 has information on
materails other than copper and aluminum used as conductors.
| |
| cr500r 2007-03-08, 5:25 pm |
| OK,
let's make sure I've got it right:
lamp operates at around 1500W 260V, with the current around 4.2A (steady
state)
Transient of 15A at startup.
Thickness 0.000254 meters stainless steel 304,
a length of .012 meters
area of 836e-006 meters squeared. ( is this the cross sectional area, or
the surface area of one side, or what?)
resistivity of 7.2e-007 ohms per meter (is this right?)
So it's not a wire, its a piece of thin (0.254mm) stainless sheet metal 12cm
long and how wide?
| |
| cr500r 2007-03-08, 5:25 pm |
| I think I figured it out from equations I found here:
http://www.polarinstruments.com/support/cits/AP144.html
If I'm guessing at your numbers right, then the below should be true:
cross area 0.000836 m^2
thickness 0.000254 m
length 0.012 m
resistivity 7.20E-07
R = r*L/A 1.03E-05 Ohms of track
where
R is the end-to-end track resistance in Ohms
r is the resistivity of the track material in Ohm Metres
L is the track length in metres
A is the track cross sectional area in square metres
I^2 R = 2.33E-03
2.33 milliwatts will be dissipated at 15A
I think you're safe if the above is true, by an order of magnitude
Also I found this: http://hypertextbook.com/facts/2006/UmranUgur.shtml
6.897E-07 ohm-m for 304 steel, even better!
| |
| edannemiller2002@yahoo.com 2007-03-08, 5:25 pm |
| On Mar 8, 4:55 pm, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
> OK,
> let's make sure I've got it right:
>
> lamp operates at around 1500W 260V, with the current around 4.2A (steady
> state)
> Transient of 15A at startup.
> Thickness 0.000254 meters stainless steel 304,
> a length of .012 meters
> area of 836e-006 meters squeared. ( is this the cross sectional area, or
> the surface area of one side, or what?)
>
> resistivity of 7.2e-007 ohms per meter (is this right?)
>
> So it's not a wire, its a piece of thin (0.254mm) stainless sheet metal 12cm
> long and how wide?
The .836e-006m^2 is the surface area of the metal. The resistivity
value is 7.2e-007 ohm-m at 20 degrees celcius. The length is actually
12 mm (I wrote the wrong unit before) and width is 5.3mm. It is a
very thin, small piece of stainless sheet metal, which is why I think
i'm having so much trouble. It is much easier to figure out the
amount of current a wire can carry, mainly due to the fact there is
tons of information out there about wire ampacity. Once again I
appreciate all your help on this topic.
Thanks,
-Erik
| |
| cr500r 2007-03-08, 5:25 pm |
| OK,
updated with the new numbers:
width 0.0053 m
thickness 0.000254 m
length 0.012 m
cross area=width*thickness 1.3462E-06 m^2
resistivity 7.20E-07
R = r*L/A 6.42E-03 Ohms of track
where
R is the end-to-end track resistance in Ohms
r is the resistivity of the track material in Ohm Metres
L is the track length in metres
A is the track cross sectional area in square metres
I^2 R = 1.44E+00
1.44 watts will be dissipated at 15A
1.13E-01
0.113 Watts will be dissipated at 4.2A
A little higher, but still not bad.
<edannemiller2002@yahoo.com> wrote in message
news:1173393839.401211.210980@64g2000cwx.googlegroups.com...
> On Mar 8, 4:55 pm, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
>
>
> The .836e-006m^2 is the surface area of the metal. The resistivity
> value is 7.2e-007 ohm-m at 20 degrees celcius. The length is actually
> 12 mm (I wrote the wrong unit before) and width is 5.3mm. It is a
> very thin, small piece of stainless sheet metal, which is why I think
> i'm having so much trouble. It is much easier to figure out the
> amount of current a wire can carry, mainly due to the fact there is
> tons of information out there about wire ampacity. Once again I
> appreciate all your help on this topic.
>
> Thanks,
>
> -Erik
>
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On 8 Mar 2007 05:22:43 -0800, edannemiller2002@yahoo.com Gave us:
>On Mar 8, 3:04 am, MassiveProng
><MassivePr...@thebarattheendoftheuniverse.org> wrote:
>
>I did pay attention is school...most of the time. The piece of metal
>will be welded to the base of a lamp (1500W lamp). I just want to be
>able to calculate the amount of current that can pass through the
>material before the temperature rise becomes too great. Sorry for
>asking a question
>
I was talking to the other person that top posted, not you.
You didn't do anything incorrectly, until you forgot how to trace a
thread or even read the fact that I quoted HIM in my response to HIM.
It's ok though dude. If you are worried, back up the steel with a
copper strap along it.
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On Thu, 08 Mar 2007 15:46:59 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
>It never ceases to amaze me how
You are STILL a top posting Usenet retard.
Look up the word CONVENTION, dumbass.
Try PROTOCOL as well.
Then try TOFU over in the wiki board as it relates to USENET, you
retarded fuckhead.
You're a goddammned idiot, and are likely too fucking old, so you
are hard wired stupid, and will never get it.
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On 8 Mar 2007 10:02:46 -0800, "contrex" <mike.j.harvey@gmail.com> Gave
us:
>On 8 Mar, 15:46, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
>
>
>
>Well, here's another surprise for you. People outside the USA (They do
>exist) are going to wonder what on earth "ampacity" means, until they
>realise it's SixPack-talk for "current carrying capacity"
>
Sure, bub. Except that the term has been used for over a century,
and is taught in electronics around the world.
You were likely sleeping when it was referred to, and DEFINED as
"current carrying capacity".
You see, dipshit, some folks just like to make single word terms
that define a specific aspect of operation.
Even E=MC^2 has a far longer definition.
So get with the program, dingledorf.
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On Thu, 08 Mar 2007 18:07:25 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
Top posting, TOFU Usenet retard!
http://en.wikipedia.org/wiki/Top-posting
Learn and obey, dipshit.
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On 8 Mar 2007 10:28:21 -0800, "contrex" <mike.j.harvey@gmail.com> Gave
us:
>"If the word "ampacity" is only used in the US,
It isn't, however. So fucking get over it, boy.
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On 8 Mar 2007 10:28:21 -0800, "contrex" <mike.j.harvey@gmail.com> Gave
us:
>
>Like I said. SixPack-talk.
Like I said... you're a fucking retard.
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On 8 Mar 2007 12:36:52 -0800, edannemiller2002@yahoo.com Gave us:
>On Mar 8, 1:58 pm, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
>
>And the lamp operates at around 260V, with the current around 4.2A. I
>don't know if i mentioned that before.
The stainless would have to be an eighth inch bar stock to get hot
at 4.2 amps.
Still, I would insulate it along its length with a shroud of
non-conductive sheathing.
| |
| MassiveProng 2007-03-08, 8:25 pm |
| On Thu, 8 Mar 2007 12:31:23 -0900, "Gerald C Newton"
<electriciannospam@electrician2.com> Gave us:
>
><edannemiller2002@yahoo.com> wrote in message
>news:1173292520.420426.325940@h3g2000cwc.googlegroups.com...
>The Neher McGrath Paper published by IEEE in 1957 has information on
>materails other than copper and aluminum used as conductors.
>
Cool call/reference, G.
| |
| cr500r 2007-03-09, 9:25 am |
| Connecting two different metals and exposing them to air will cause
corrosion, adding heat will accelerate the corrosion.
BTW I'm going to keep top posting just to piss off MassiveProng, he doesn't
add anything to this group except insults.
"MassiveProng" <MassiveProng@thebarattheendoftheuniverse.org> wrote in
message news:64f1v2dk0lk7ph6clu0kmrujp23j2gvmqn@4ax.com...
.... If you are worried, back up the steel with a
> copper strap along it.
| |
| edannemiller2002@yahoo.com 2007-03-09, 9:25 am |
| On Mar 8, 5:34 pm, "cr500r" <jeffnope_nos...@hotmail.com> wrote:
> I think I figured it out from equations I found here:http://www.polarinstruments.com/support/cits/AP144.html
>
> If I'm guessing at your numbers right, then the below should be true:
>
> cross area 0.000836 m^2
>
> thickness 0.000254 m
> length 0.012 m
>
> resistivity 7.20E-07
> R = r*L/A 1.03E-05 Ohms of track
>
> where
>
> R is the end-to-end track resistance in Ohms
> r is the resistivity of the track material in Ohm Metres
> L is the track length in metres
> A is the track cross sectional area in square metres
>
> I^2 R = 2.33E-03
>
> 2.33 milliwatts will be dissipated at 15A
>
> I think you're safe if the above is true, by an order of magnitude
>
> Also I found this:http://hypertextbook.com/facts/2006/UmranUgur.shtml
>
> 6.897E-07 ohm-m for 304 steel, even better!
Cr500,
Thanks so much for the help. The explination of the subject and the
references provided were very helpful. This will be very helpful if
the piece is redesigned with different dimensions or for any reason we
use a different type of metal. I will continue to check new threads
in hope of providing help to others as you did for me.
Thanks,
-Erik
| |
| MassiveProng 2007-03-09, 9:25 pm |
| On Fri, 09 Mar 2007 15:04:03 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
>Connecting two different metals and exposing them to air will cause
>corrosion, adding heat will accelerate the corrosion.
You're an idiot. The copper bar can be insulated OR the stainless
can be. Nobody said anything about them both carrying current, nor
about them being fused or clamped together.
>
>BTW I'm going to keep top posting just to piss off MassiveProng, he doesn't
>add anything to this group except insults.
More proof that you are an Utter Usenet Retard!
Your little wussy boy calculations are just that... fucking
retarded overkill. Fact is, you contribute nothing.
| |
| cr500r 2007-03-10, 5:25 pm |
|
"MassiveProng" <MassiveProng@thebarattheendoftheuniverse.org> wrote in
message news:or84v2h0n7eu4bj4d39e8s2aa5m9smrgs0@4ax.com...
> On Fri, 09 Mar 2007 15:04:03 GMT, "cr500r"
> <jeffnope_nospam@hotmail.com> Gave us:
>
>
> You're an idiot. The copper bar can be insulated OR the stainless
> can be. Nobody said anything about them both carrying current, nor
> about them being fused or clamped together.
Sounds like backpedaling to me, why use copper if it's not going to carry
current? You don't, it's too expensive and it corrodes.
>
> More proof that you are an Utter Usenet Retard!
As far as the insults go, I rest my case.
>
> Your little wussy boy calculations are just that... fucking
> retarded overkill. Fact is, you contribute nothing.
I will let Erik defend me on this one:
"Cr500,
Thanks so much for the help. The explanation of the subject and the
references provided were very helpful. This will be very helpful if
the piece is redesigned with different dimensions or for any reason we
use a different type of metal. I will continue to check new threads
in hope of providing help to others as you did for me.
Thanks,
-Erik"
| |
| MassiveProng 2007-03-10, 5:25 pm |
| On Sat, 10 Mar 2007 21:28:40 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
>I will let Erik defend me on this one:
>
>"Cr500,
>
>Thanks so much for the help. The explanation of the subject and the
>references provided were very helpful. This will be very helpful if
>the piece is redesigned with different dimensions or for any reason we
>use a different type of metal. I will continue to check new threads
>in hope of providing help to others as you did for me.
Yeah, right. Aren't you the twit that thinks that ampacity refers to
a melting point?
Were not all your pathetic calculations based on a melting point?
The two are NOT related... at all!
You refer to FUSING point. An entirely different realm of electrical
engineering and physics.
Get a clue, dipshit. And YES, you deserve any name I throw at you
for your retarded top posting baby bullshit, especially when you even
declared that you were doing it deliberately.
I do not expect you, however, to be mature enough to see how
adolescent you are.
You are proof that numerical age does not an adult make, little boy.
| |
| cr500r 2007-03-10, 5:25 pm |
| > Yeah, right. Aren't you the twit that thinks that ampacity refers to
> a melting point?
>
> Were not all your pathetic calculations based on a melting point?
No, Erik started off with the melting point, then he realised it wasn't part
of the solution.
My calculations proved that the stainless steel he had in mind would work.
First you think those calculations are overkill, and now they are pathetic.
I guess that means you don't understand them
>
> The two are NOT related... at all!
>
> You refer to FUSING point. An entirely different realm of electrical
> engineering and physics.
Further proving you don't understand, Erik understood, why can't you?
>
> Get a clue, dipshit. And YES, you deserve any name I throw at you
> for your retarded top posting baby bullshit, especially when you even
> declared that you were doing it deliberately.
>
> I do not expect you, however, to be mature enough to see how
> adolescent you are.
>
> You are proof that numerical age does not an adult make, little boy.
I must admit it's a little fun to see you rant and rave, but I'm bored now.
| |
| MassiveProng 2007-03-10, 5:25 pm |
| On Sat, 10 Mar 2007 22:12:52 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
>First you think those calculations are overkill, and now they are pathetic.
>I guess that means you don't understand them
That's about as retarded an assessment as any other you make.
Understand them?
Ha!
At a mere 4.2 amps, a fucking tenth inch diameter SS rod would work,
you fucking retard, and I do NOT need ANY figures for that one.
Get a clue.
Dude, you are fucking STOOPID in the extreme.
| |
| MassiveProng 2007-03-10, 5:25 pm |
| On Sat, 10 Mar 2007 22:12:52 GMT, "cr500r"
<jeffnope_nospam@hotmail.com> Gave us:
>
>Further proving you don't understand, Erik understood, why can't you?
You have not proven anything... ever. Not in this group or anywhere
else. The only thing you have proven is that you ignore standards and
conventions due to being a lazy TOFU fucktard.
That alone should have gotten you ignored by all from the get go.
| |
|
| On Mar 9, 12:56 pm, MassiveProng
<MassivePr...@thebarattheendoftheuniverse.org> wrote:
> On 8 Mar 2007 10:28:21 -0800, "contrex" <mike.j.har...@gmail.com> Gave
> us:
>
>
> It isn't, however. So fucking get over it, boy.
Ampacity. It's not used in the UK. It's not used in Australia. It is
used (apparently) in the USA. Would other group members care to
volunteer if it is used in their countries? Does anybody use
Wattacity, Voltacity or Ohmacity? methinks not. Just another
Americanism that has caught on in some very small way in other
countries.
BTW I think 'Massiveprong' has a real problem as regards criticising
peoples usenet ettiquite.....and then hurls a barrage of crude, filthy
insults...as if that is an example of correct usenet ettiquite. Clean
up your language, buddy. There is no room (or need) for that kind of
language here. You wouldn't say that to his face...nor should u say
that here.
As far as the original posted question is concerned....neher mcgrath
calcs can give u all u need as regards calculating the maximum current
carrying capacity of your system. There are other older empirical
formulae that can help.
Danny
| |
|
| Danny wrote:
> On Mar 9, 12:56 pm, MassiveProng
> <MassivePr...@thebarattheendoftheuniverse.org> wrote:
>
>
>
> Ampacity. It's not used in the UK. It's not used in Australia. It is
> used (apparently) in the USA. Would other group members care to
> volunteer if it is used in their countries? Does anybody use
> Wattacity, Voltacity or Ohmacity? methinks not. Just another
> Americanism that has caught on in some very small way in other
> countries.
"Ampacity" is a major term used in the US National Electrical Code and
is a useful and commonly used word in the US, and presumably some other
areas. It is certainly no odder than various UK-isms. Unfamiliar terms
occurr in newsgroups with an international following. Just ask what it
means.
> BTW I think 'Massiveprong' has a real problem ....
S/he is usually a troll. I don't understand why s/he isn't just ignored.
--
bud--
| |
| MassiveProng 2007-03-12, 3:25 am |
| On 11 Mar 2007 22:43:22 -0700, "Danny" <dindyk@energy.com.au> Gave us:
>BTW I think 'Massiveprong' has a real problem as regards criticising
>peoples usenet ettiquite.....and then hurls a barrage of crude, filthy
>insults...as if that is an example of correct usenet ettiquite.
Fuck netiquette and fuck you. It's called free speech.
At least I know that chrono posting is proper, and doing it like
Bill Gates' e-mail client is just plain fucking retarded and lazy. So
don't be a TOFU fucking Usenet retard, and I won't call you one,
fucktard!
| |
| MassiveProng 2007-03-12, 3:25 am |
| On 11 Mar 2007 22:43:22 -0700, "Danny" <dindyk@energy.com.au> Gave us:
>Ampacity. It's not used in the UK. It's not used in Australia. It is
>used (apparently) in the USA. Would other group members care to
>volunteer if it is used in their countries? Does anybody use
>Wattacity, Voltacity or Ohmacity? methinks not.
Methinks you're just being retarded now.
>Just another
>Americanism that has caught on in some very small way in other
>countries.
Ever use the term "Voltage" or "Wattage"? Technically, neither of
those are real terms either. You need to face the fact that you terms
list is not the be all end all fact sheet, dumbass.
Hey... I got one... describe for me what a "dry solder joint" is, if
you have any balls, boy
I'll bet you can't, yet it has been in use in the industry for
decades.
This should be funny...
| |
| MassiveProng 2007-03-12, 3:25 am |
| On 11 Mar 2007 22:43:22 -0700, "Danny" <dindyk@energy.com.au> Gave us:
> Clean
>up your language, buddy.
Fuck off, jack-off. Not your buddy.
| |
| MassiveProng 2007-03-12, 3:25 am |
| On Mon, 12 Mar 2007 01:57:42 -0600, Bud-- <remove.BudNews@isp.com>
Gave us:
>
>S/he is usually a troll. I don't understand why s/he isn't just ignored.
>
Certainly not due to any retarded asswipe assessments a dipshit like
you makes.
| |
|
| On Mar 12, 6:41 pm, MassiveProng
<MassivePr...@thebarattheendoftheuniverse.org> wrote:
> On 11 Mar 2007 22:43:22 -0700, "Danny" <din...@energy.com.au> Gave us:
>
>
> Fuck off, jack-off. Not your buddy.
make up ur mind....i can't do both at the same
time.......................buddy
| |
| MassiveProng 2007-03-16, 3:25 am |
| On 15 Mar 2007 19:04:23 -0700, "Danny" <dindyk@energy.com.au> Gave us:
>On Mar 12, 6:41 pm, MassiveProng
><MassivePr...@thebarattheendoftheuniverse.org> wrote:
>
>make up ur mind....i can't do both at the same
>time.......................buddy
Get a clue, dipshit.
It means fuck off, you ignorant jack off.
Since you cannot even capitalize the woird "I", I cannot expect a
total fucking retard like you to get a simple remark.
Oh, and the ellipsis is only THREE periods to be correct, not your
retarded twenty. Oh, that's right... a word like that is likely way
over your head too.
| |
|
| On Mar 16, 3:24 pm, MassiveProng
<MassivePr...@thebarattheendoftheuniverse.org> wrote:
> On 15 Mar 2007 19:04:23 -0700, "Danny" <din...@energy.com.au> Gave us:
>
>
>
>
>
> Get a clue, dipshit.
>
> It means fuck off, you ignorant jack off.
>
> Since you cannot even capitalize the woird "I", I cannot expect a
> total fucking retard like you to get a simple remark.
>
> Oh, and the ellipsis is only THREE periods to be correct, not your
> retarded twenty. Oh, that's right... a word like that is likely way
> over your head too.
It should read "likely to be way over your head" to be correct.
Sharpen up pea-brain. And capitalize the 'woird'...you're a sad, sad
man.
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