| Aditya 2008-04-01, 9:25 am |
| On Mar 31, 10:35 pm, Palindrome <m...@privacy.net> wrote:
> Aditya wrote:
>
>
>
>
> You have now (partially) defined the environment. Which you hadn't done
> in the original question. Now define the application. There are still a
> myriad of possible answers.
>
> Including the obvious one that should always be considered first in any
> experiment. Instrumentation error.
>
> The next obvious is that the new source has frequency components such as
> to excede the dv/dt rating of the thyristor. This may be because the
> fundamental frequency has changed, or because it is no longer a simple
> sinusoid (eg has harmonics..square wave, perhaps?), or because it has
> superimposed noise, etc.
>
> The next obvious is that energy is being injected into the junctions by
> another route. eg the thyristor has a transparent case and a high level
> of incident radiation (visible or invisible) is being directed on it.
>
> The next obvious..
>
> Sorry, the list goes on and on and on. I repeat, it was a stupid
> question to ask of intelligent students who understand the underlying
> principles of electronic devices.
>
> --
> Sue
oK... thx for the answers..
|